\(\int \frac {x}{\sqrt [3]{-a+b x}} \, dx\) [401]

Optimal result

Integrand size = 13, antiderivative size = 38 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 a (-a+b x)^{2/3}}{2 b^2}+\frac {3 (-a+b x)^{5/3}}{5 b^2} \]

[Out]

3/2*a*(b*x-a)^(2/3)/b^2+3/5*(b*x-a)^(5/3)/b^2

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {45} \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 (b x-a)^{5/3}}{5 b^2}+\frac {3 a (b x-a)^{2/3}}{2 b^2} \]

[In]

Int[x/(-a + b*x)^(1/3),x]

[Out]

(3*a*(-a + b*x)^(2/3))/(2*b^2) + (3*(-a + b*x)^(5/3))/(5*b^2)

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a}{b \sqrt [3]{-a+b x}}+\frac {(-a+b x)^{2/3}}{b}\right ) \, dx \\ & = \frac {3 a (-a+b x)^{2/3}}{2 b^2}+\frac {3 (-a+b x)^{5/3}}{5 b^2} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.68 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 (-a+b x)^{2/3} (3 a+2 b x)}{10 b^2} \]

[In]

Integrate[x/(-a + b*x)^(1/3),x]

[Out]

(3*(-a + b*x)^(2/3)*(3*a + 2*b*x))/(10*b^2)

Maple [A] (verified)

Time = 0.07 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.61

method	result	size
gosper	\(\frac {3 \left (2 b x +3 a \right ) \left (b x -a \right )^{\frac {2}{3}}}{10 b^{2}}\)	\(23\)
trager	\(\frac {3 \left (2 b x +3 a \right ) \left (b x -a \right )^{\frac {2}{3}}}{10 b^{2}}\)	\(23\)
pseudoelliptic	\(\frac {3 \left (2 b x +3 a \right ) \left (b x -a \right )^{\frac {2}{3}}}{10 b^{2}}\)	\(23\)
risch	\(-\frac {3 \left (-b x +a \right ) \left (2 b x +3 a \right )}{10 b^{2} \left (b x -a \right )^{\frac {1}{3}}}\)	\(29\)
derivativedivides	\(\frac {\frac {3 \left (b x -a \right )^{\frac {5}{3}}}{5}+\frac {3 a \left (b x -a \right )^{\frac {2}{3}}}{2}}{b^{2}}\)	\(30\)
default	\(\frac {\frac {3 \left (b x -a \right )^{\frac {5}{3}}}{5}+\frac {3 a \left (b x -a \right )^{\frac {2}{3}}}{2}}{b^{2}}\)	\(30\)

[In]

int(x/(b*x-a)^(1/3),x,method=_RETURNVERBOSE)

[Out]

3/10/b^2*(2*b*x+3*a)*(b*x-a)^(2/3)

Fricas [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.58 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 \, {\left (2 \, b x + 3 \, a\right )} {\left (b x - a\right )}^{\frac {2}{3}}}{10 \, b^{2}} \]

[In]

integrate(x/(b*x-a)^(1/3),x, algorithm="fricas")

[Out]

3/10*(2*b*x + 3*a)*(b*x - a)^(2/3)/b^2

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.79 (sec) , antiderivative size = 486, normalized size of antiderivative = 12.79 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\begin {cases} - \frac {9 a^{\frac {11}{3}} \left (-1 + \frac {b x}{a}\right )^{\frac {2}{3}} e^{\frac {i \pi }{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} - \frac {9 a^{\frac {11}{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} + \frac {3 a^{\frac {8}{3}} b x \left (-1 + \frac {b x}{a}\right )^{\frac {2}{3}} e^{\frac {i \pi }{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} + \frac {9 a^{\frac {8}{3}} b x}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} + \frac {6 a^{\frac {5}{3}} b^{2} x^{2} \left (-1 + \frac {b x}{a}\right )^{\frac {2}{3}} e^{\frac {i \pi }{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} & \text {for}\: \left |{\frac {b x}{a}}\right | > 1 \\\frac {9 a^{\frac {11}{3}} \left (1 - \frac {b x}{a}\right )^{\frac {2}{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} - \frac {9 a^{\frac {11}{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} - \frac {3 a^{\frac {8}{3}} b x \left (1 - \frac {b x}{a}\right )^{\frac {2}{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} + \frac {9 a^{\frac {8}{3}} b x}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} - \frac {6 a^{\frac {5}{3}} b^{2} x^{2} \left (1 - \frac {b x}{a}\right )^{\frac {2}{3}}}{- 10 a^{2} b^{2} e^{\frac {i \pi }{3}} + 10 a b^{3} x e^{\frac {i \pi }{3}}} & \text {otherwise} \end {cases} \]

[In]

integrate(x/(b*x-a)**(1/3),x)

[Out]

Piecewise((-9*a**(11/3)*(-1 + b*x/a)**(2/3)*exp(I*pi/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp(I*pi/3))
- 9*a**(11/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp(I*pi/3)) + 3*a**(8/3)*b*x*(-1 + b*x/a)**(2/3)*exp(I
*pi/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp(I*pi/3)) + 9*a**(8/3)*b*x/(-10*a**2*b**2*exp(I*pi/3) + 10*
a*b**3*x*exp(I*pi/3)) + 6*a**(5/3)*b**2*x**2*(-1 + b*x/a)**(2/3)*exp(I*pi/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a
*b**3*x*exp(I*pi/3)), Abs(b*x/a) > 1), (9*a**(11/3)*(1 - b*x/a)**(2/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*
x*exp(I*pi/3)) - 9*a**(11/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp(I*pi/3)) - 3*a**(8/3)*b*x*(1 - b*x/a
)**(2/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp(I*pi/3)) + 9*a**(8/3)*b*x/(-10*a**2*b**2*exp(I*pi/3) + 1
0*a*b**3*x*exp(I*pi/3)) - 6*a**(5/3)*b**2*x**2*(1 - b*x/a)**(2/3)/(-10*a**2*b**2*exp(I*pi/3) + 10*a*b**3*x*exp
(I*pi/3)), True))

Maxima [A] (verification not implemented)

none

Time = 0.20 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.79 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 \, {\left (b x - a\right )}^{\frac {5}{3}}}{5 \, b^{2}} + \frac {3 \, {\left (b x - a\right )}^{\frac {2}{3}} a}{2 \, b^{2}} \]

[In]

integrate(x/(b*x-a)^(1/3),x, algorithm="maxima")

[Out]

3/5*(b*x - a)^(5/3)/b^2 + 3/2*(b*x - a)^(2/3)*a/b^2

Giac [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.76 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {3 \, {\left (2 \, {\left (b x - a\right )}^{\frac {5}{3}} + 5 \, {\left (b x - a\right )}^{\frac {2}{3}} a\right )}}{10 \, b^{2}} \]

[In]

integrate(x/(b*x-a)^(1/3),x, algorithm="giac")

[Out]

3/10*(2*(b*x - a)^(5/3) + 5*(b*x - a)^(2/3)*a)/b^2

Mupad [B] (verification not implemented)

Time = 0.03 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.76 \[ \int \frac {x}{\sqrt [3]{-a+b x}} \, dx=\frac {15\,a\,{\left (b\,x-a\right )}^{2/3}+6\,{\left (b\,x-a\right )}^{5/3}}{10\,b^2} \]

[In]

int(x/(b*x - a)^(1/3),x)

[Out]

(15*a*(b*x - a)^(2/3) + 6*(b*x - a)^(5/3))/(10*b^2)